The electronic configuration of Cu is

Question

The electronic configuration of Cu is (A) [Ne]3s23p63d94s2 (B) [Ne]3s23p63d104s1 (C) [Ne]3s23p63d34s24p6 (D) [Ne]3s23p63d54s24p4

Tardigrade Admin · Accepted Answer

Atomic number of Cu is 29 . Thus, its electronic configuration can be written as Cu 29=1 s2, 2 s2, 2 p6, 3 s2, 3 p6, 3 d10, 4 s1 (Since, fully filled orbitals are more stable, so one electron from 4 s orbital transfers into 3 d orbital.) The electronic configuration of neon is Ne 10=1 s2, 2 s2, 2 p6 Thus, using inert gas, the configuration of Cu can also be represented as Cu 2 θ=[ Ne ] 3 s2, 3 p8, 3 d10, 4 s1

Q. The electronic configuration of $C u$ is

$[N e] 3 s^{2} 3 p^{6} 3 d^{9} 4 s^{2}$

$[N e] 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1}$

$[N e] 3 s^{2} 3 p^{6} 3 d^{3} 4 s^{2} 4 p^{6}$

$[N e] 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{2} 4 p^{4}$

Q. The electronic configuration of Cu is

[Ne]3s23p63d94s2

[Ne]3s23p63d104s1

[Ne]3s23p63d34s24p6

[Ne]3s23p63d54s24p4

Q. The electronic configuration of $C u$ is

$[N e] 3 s^{2} 3 p^{6} 3 d^{9} 4 s^{2}$

$[N e] 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1}$

$[N e] 3 s^{2} 3 p^{6} 3 d^{3} 4 s^{2} 4 p^{6}$

$[N e] 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{2} 4 p^{4}$