The electron emitted in beta radiation originates from

Question

The electron emitted in beta radiation originates from (A) inner orbits of atom (B) free electron existing in nuclei (C) decay of neutron in the nucleus (D) photon escaping from the nucleus

Tardigrade Admin · Accepted Answer

In beta decay, a beta minus particle (β -) is an electron emission of β involves, transfor-mation of a neutron into a proton an electron and a third particle called an anti-neutrin ( barv). 0n1= 1p1+ -1 β 0+ barv

Q. The electron emitted in beta radiation originates from

inner orbits of atom

free electron existing in nuclei

decay of neutron in the nucleus

photon escaping from the nucleus

In beta decay, a beta minus particle $(β^{-})$ is an electron emission of $β$ involves, transfor-mation of a neutron into a proton an electron and a third particle called an anti-neutrin $(\overset{v}{ˉ}) .$ $_{0} n^{1} =_{1} p^{1} +_{- 1} β^{0} + \overset{v}{ˉ}$

Q. The electron emitted in beta radiation originates from

inner orbits of atom

free electron existing in nuclei

decay of neutron in the nucleus

photon escaping from the nucleus

In beta decay, a beta minus particle (β−) is an electron emission of β involves, transfor-mation of a neutron into a proton an electron and a third particle called an anti-neutrin (vˉ). 0​n1=1​p1+−1​β0+vˉ

In beta decay, a beta minus particle $(β^{-})$ is an electron emission of $β$ involves, transfor-mation of a neutron into a proton an electron and a third particle called an anti-neutrin $(\overset{v}{ˉ}) .$ $_{0} n^{1} =_{1} p^{1} +_{- 1} β^{0} + \overset{v}{ˉ}$