The electrode reaction that takes place at the anode of CH4 - O2 fuel cell is

Question

The electrode reaction that takes place at the anode of CH4 - O2 fuel cell is (A) 2O2 + 8H+ + 8e- arrow 4H2O (B) CH4 + 2H2 O arrow CO2 + 8H+ + 8e-  (C) CH4 + 2O2 arrow CO2 + 2H2 O (D) 2H+ + 2e- arrow H2

Tardigrade Admin · Accepted Answer

At anode the following reaction takes place CH4 + 2H2 O arrow CO2 + 8H+ + 8e-

Q. The electrode reaction that takes place at the anode of CH₄ - O₂ fuel cell is

$2 O_{2} + 8 H^{+} + 8 e^{-} \to 4 H_{2} O$

$C H_{4} + 2 H_{2} O \to C O_{2} + 8 H^{+} + 8 e^{-}$

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

$2 H^{+} + 2 e^{-} \to H_{2}$

At anode the following reaction takes place $C H_{4} + 2 H_{2} O \to C O_{2} + 8 H^{+} + 8 e^{-}$

Q. The electrode reaction that takes place at the anode of CH4 - O2 fuel cell is

2O2​+8H++8e−→4H2​O

CH4​+2H2​O→CO2​+8H++8e−

CH4​+2O2​→CO2​+2H2​O

2H++2e−→H2​