The electric field part of an electromagnetic wave in vacuum is E = 3.1 (N/C) cos [(1.8 (rad/m)) y + (5.4 × 108 (rad/s))t] hati, the frequency corresponding to the given part of electromagnetic wave is

Question

The electric field part of an electromagnetic wave in vacuum is E = 3.1 (N/C) cos [(1.8 (rad/m)) y + (5.4 × 108 (rad/s))t] hati, the frequency corresponding to the given part of electromagnetic wave is (A) 5.4 × 108 Hz (B) 8.6 × 107 Hz (C) 3.2 × 108 Hz (D) 4.8 × 107 Hz

Tardigrade Admin · Accepted Answer

Frequency, upsilon = (ω/2π) = (5.4 × 108 × 7/2 × 22) = 8.6 × 107 Hz

Q. The electric field part of an electromagnetic wave in vacuum is
$E = 3.1 \frac{N}{C} cos [(1.8 \frac{r a d}{m}) y + (5.4 \times 1 0^{8} \frac{r a d}{s}) t] \hat{i}$ , the frequency corresponding to the given part of electromagnetic wave is

$5.4 \times 1 0^{8} Hz$

$8.6 \times 1 0^{7} Hz$

$3.2 \times 1 0^{8} Hz$

$4.8 \times 1 0^{7} Hz$

Frequency,
$υ = \frac{ω}{2 π} = \frac{5.4 \times 1 0 ^{8} \times 7}{2 \times 22}$
$= 8.6 \times 1 0^{7} Hz$

Q. The electric field part of an electromagnetic wave in vacuum is E=3.1CN​cos[(1.8mrad​)y+(5.4×108srad​)t]i^, the frequency corresponding to the given part of electromagnetic wave is

5.4×108Hz

8.6×107Hz

3.2×108Hz

4.8×107Hz