The electric field in a region is given by vecE = (Ax + B) hati , where E is in NC-1 and x is in metres. The values of constants are A = 20 SI unit and B = 10 SI unit. If the potential at x = 1 is V1 and that at x = -5 is V2, then V1 - V2 is :-

Question

The electric field in a region is given by vecE = (Ax + B) hati , where E is in NC-1 and x is in metres. The values of constants are A = 20 SI unit and B = 10 SI unit. If the potential at x = 1 is V1 and that at x = -5 is V2, then V1 - V2 is :- (A) - 48 V (B) - 520 V (C) 180 V (D) 320 V

Tardigrade Admin · Accepted Answer

vecE = (20x +10) hati V1 -V2 - ∫1-5 (20x+10)dx V1 - V2 = -(10x2 + 10x)1-5 V1 - V2 = 10(25 - 5 - 1 - 1) V1 - V2 = 180 V

Q. The electric field in a region is given by $E = (A x + B) \hat{i}$ , where E is in $N C^{- 1}$ and x is in metres. The values of constants are $A = 20 S I$ unit and $B = 10 S I$ unit. If the potential at x = 1 is $V_{1}$ and that at $x = - 5$ is $V_{2}$ , then $V_{1} - V_{2}$ is :-

- 48 V

- 520 V

180 V

320 V

$E = (20 x + 10) \hat{i}$
$V_{1} - V_{2} - \int_{- 5}^{1} (20 x + 10) d x$
$V_{1} - V_{2} = - (10 x^{2} + 10 x)_{- 5}^{1}$
$V_{1} - V_{2} = 10 (25 - 5 - 1 - 1)$
$V_{1} - V_{2} = 180 V$

Q. The electric field in a region is given by E=(Ax+B)i^ , where E is in NC−1 and x is in metres. The values of constants are A=20SI unit and B=10SI unit. If the potential at x = 1 is V1​ and that at x=−5 is V2​, then V1​−V2​ is :-