The e.m.f. of the cell Tl| Tl+ (0.001 M) | | Cu2+ (0.01 M)|Cu is 0.83 V. The emf of this cell could be increased by

Question

The e.m.f. of the cell Tl| Tl+ (0.001 M) | | Cu2+ (0.01 M)|Cu is 0.83 V. The emf of this cell could be increased by (A) increasing the concentration of Tl+ ions (B) increasing the concentration of Cu2+ ions (C) increasing the concentration of both (D) none of the above

Tardigrade Admin · Accepted Answer

Ecell = E0 cell + (0.059/n) log ([Cu+2]/[Tl+]2) increasing cone, of Cu+2 ions increases the emf.

Q. The e.m.f. of the cell $Tl ∣ T l^{+} (0.001 M) ∣∣ C u^{2 +} (0.01 M) ∣ C u i s 0.83 V$ . The emf of this cell could be increased by

increasing the concentration of $T l^{+}$ ions

increasing the concentration of $C u^{2 +}$ ions

increasing the concentration of both

none of the above

$E_{ce ll} = E_{ce ll}^{0} + \frac{0.059}{n} l o g \frac{[ C u ^{+ 2} ]}{[ T l ^{+} ] ^{2}}$
increasing cone, of $C u^{+ 2}$ ions increases the emf.

Q. The e.m.f. of the cell Tl∣Tl+(0.001M)∣∣Cu2+(0.01M)∣Cuis0.83V. The emf of this cell could be increased by

increasing the concentration of Tl+ ions

increasing the concentration of Cu2+ ions