Tardigrade
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Tardigrade
Question
Chemistry
The E°M3+/ M2+ values for Cr, Mn, Fe and Co are 0.41,+ 1.57, + 0.77 and +1.97 V, respectively. For which one of these metals the change in oxidation state from +2 to + 3 is easiest?
Q. The
E
M
3
+
/
M
2
+
∘
values for
C
r
,
M
n
,
F
e
and
C
o
are
0.41
,
+
1.57
,
+
0.77
and
+
1.97
V
, respectively. For which one of these metals the change in oxidation state from
+
2
to
+
3
is easiest?
6351
200
UPSEE
UPSEE 2015
Report Error
A
C
r
B
M
n
C
F
e
D
C
o
Solution:
E
C
r
3
+
/
C
r
2
+
∘
=
−
0.41
V
E
M
n
3
+
/
M
n
2
+
∘
=
+
1.57
V
E
∘
F
e
3
+
/
F
e
2
+
=
+
0.77
V
E
C
o
3
+
/
C
0
2
+
∘
=
+
1.9
More negative value of
E
red
∘
indicates better reducing agent, thus easily oxidised. Thus, oxidation of
C
r
2
+
to
C
r
3
+
is the easiest.