Question

The domain of the function $f(x)=\frac{\sqrt{x+2}}{x^2-9}$ is

• A. $(-\infty ,-3)\cup [2,\infty )$
• B. $[2,3)$
• C. $[-2,3)\cup (3,\infty )$
• D. $(-\infty ,-3)\cup (3,\infty )$

Answer 1

Answer: (C)

$x+2\ge 0\Rightarrow x\ge -2$
$x^2-9\ne 0\Rightarrow x\ne \pm 3$
$[-2,3)\cup (3,\infty$