Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The domain and range of relation R = (x , y ) /x , y ∈ N , x + 2y = 5 is
Q. The domain and range of relation
R
=
{(
x
,
y
)
/
x
,
y
∈
N
,
x
+
2
y
=
5
}
is
1810
186
Relations and Functions
Report Error
A
{
1
,
3
}
,
{
2
,
1
}
49%
B
{
2
,
1
}
,
{
3
,
2
}
19%
C
{
1
,
3
}
,
{
1
,
1
}
14%
D
{
1
,
2
}
,
{
1
,
3
}
19%
Solution:
x
+
y
=
5
⇒
x
∈
N
.
y
∈
N
Domain .= Set of values of
x
=
{
1
,
3
}
Range = Set of values of
y
=
{
1
,
2
}