Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The distance of the point P(a, b, c) from the x-axis is
Q. The distance of the point
P
(
a
,
b
,
c
)
from the
x
-axis is
2001
255
Introduction to Three Dimensional Geometry
Report Error
A
b
2
+
c
2
74%
B
a
2
+
c
2
7%
C
a
2
+
b
2
11%
D
None of these
8%
Solution:
The coordinates of the foot of the perpendicular from
P
on
x
-axis are (
a
,
0
,
0
). Therefore, the required distance is
(
a
−
a
)
2
+
(
b
−
0
)
2
+
(
c
−
0
)
2
=
b
2
+
c
2
.