Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The distance of the point P(2,-3,4) from the plane r⋅( hati+ hatj+ hatk)=5 measured parallel to z-axis, is
Q. The distance of the point
P
(
2
,
−
3
,
4
)
from the plane
r
⋅
(
i
^
+
j
^
+
k
^
)
=
5
measured parallel to
z
-axis, is
178
97
Vector Algebra
Report Error
A
1
B
2
C
2
D
4
Solution:
Equation of plane is
x
+
y
+
z
=
5
Straight line passing through
(
2
,
−
3
,
4
)
and parallel to
z
-axis
0
x
−
2
=
0
y
+
3
=
1
z
−
4
=
r
a point on the line is
(
2
,
−
3
,
r
+
4
)
which lies on the plane
x
+
y
+
z
=
5
∴
2
−
3
+
r
+
4
=
5
⇒
r
=
2
Hence, required distance is
=
2