The distance of the line of intersection of planes x+y+z+1=0 and x-y+2z+1=0 from the plane 3x+y+4z+7=0 , is

Question

The distance of the line of intersection of planes x+y+z+1=0 and x-y+2z+1=0 from the plane 3x+y+4z+7=0 , is (A) (2/√26) units (B) (1/√26) units (C) (4/√26) units (D) (7/√26) units

Tardigrade Admin · Accepted Answer

Q. The distance of the line of intersection of planes $x + y + z + 1 = 0$ and $x - y + 2 z + 1 = 0$ from the plane $3 x + y + 4 z + 7 = 0$ , is

$\frac{2}{26}$ units

$\frac{1}{26}$ units

$\frac{4}{26}$ units

$\frac{7}{26}$ units

Q. The distance of the line of intersection of planes x+y+z+1=0 and x−y+2z+1=0 from the plane 3x+y+4z+7=0 , is

26​2​ units

26​1​ units

26​4​ units

26​7​ units

Q. The distance of the line of intersection of planes $x + y + z + 1 = 0$ and $x - y + 2 z + 1 = 0$ from the plane $3 x + y + 4 z + 7 = 0$ , is

$\frac{2}{26}$ units

$\frac{1}{26}$ units

$\frac{4}{26}$ units

$\frac{7}{26}$ units