The dissolution of Al(O H)3 by a solution of NaOH results in the formation of:

Question

The dissolution of Al(O H)3 by a solution of NaOH results in the formation of: (A) [ Al ( H 2 O )4( OH )2]+ (B) [A l (H2 O)3 (O H)3] (C) [ Al ( H 2 O )2( OH )4]- (D) [A l (H2 O)6 (O H)3]

Tardigrade Admin · Accepted Answer

Al(O H)3 dissolve in NaOH solution to give Al(O H)4- ion which is supposed to have the octahedral complex species ([A l (O H)4 (H2 O)2])- in aqueous solution Al ( OH )3+ NaOH ( aq ) arrow[ Al ( OH )4( H 2 O )2]-( aq )+ Na +( aq )

Q. The dissolution of $A l (O H)_{3}$ by a solution of $N a O H$ results in the formation of:

$[A l (H_{2} O)_{4} (O H)_{2}]^{+}$

$[A l (H_{2} O)_{3} (O H)_{3}]$

$[A l (H_{2} O)_{2} (O H)_{4}]^{-}$

$[A l (H_{2} O)_{6} (O H)_{3}]$

$A l (O H)_{3}$ dissolve in $N a O H$ solution to give $A l (O H)_{4}^{-}$ ion which is supposed to have the octahedral complex species $([A l (O H)_{4} (H_{2} O)_{2}])^{-}$ in aqueous solution
$A l (O H)_{3} + N a O H (a q) \to [A l (O H)_{4} (H_{2} O)_{2}]^{-} (a q) + N a^{+} (a q)$

Q. The dissolution of Al(OH)3​ by a solution of NaOH results in the formation of:

[Al(H2​O)4​(OH)2​]+

[Al(H2​O)3​(OH)3​]

[Al(H2​O)2​(OH)4​]−

[Al(H2​O)6​(OH)3​]