The displacement time graph of a moving particle is shown below. The instantaneous velocity of the particle is negative at the point

Question

The displacement time graph of a moving particle is shown below. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-k56xlito4dz13qq7.jpg" /> The instantaneous velocity of the particle is negative at the point (A)  textC (B)  textE (C)  textD (D)  textF

Tardigrade Admin · Accepted Answer

At E, the slope of the curve is negative. For a displacement-time graph, the slope at a point represents the instantaneous velocity. So, at E, instantaneous velocity is - textv texte as the slope is - textv texte .

Q. The displacement time graph of a moving particle is shown below.

The instantaneous velocity of the particle is negative at the point

$C$

$E$

$D$

$F$

At $E,$ the slope of the curve is negative. For a displacement-time graph, the slope at a point represents the instantaneous velocity. So, at $E,$ instantaneous velocity is $- v e$ as the slope is $- v e$ .

Q. The displacement time graph of a moving particle is shown below. The instantaneous velocity of the particle is negative at the point

C

E

D

F

At E, the slope of the curve is negative. For a displacement-time graph, the slope at a point represents the instantaneous velocity. So, at E, instantaneous velocity is −ve as the slope is −ve .

Q. The displacement time graph of a moving particle is shown below.

The instantaneous velocity of the particle is negative at the point

$C$

$E$

$D$

$F$

At $E,$ the slope of the curve is negative. For a displacement-time graph, the slope at a point represents the instantaneous velocity. So, at $E,$ instantaneous velocity is $- v e$ as the slope is $- v e$ .