The displacement-time graph for two sound waves A and B are shown in the figure, then the ratio of their intensities IA / IB is equal to

Question

The displacement-time graph for two sound waves A and B are shown in the figure, then the ratio of their intensities IA / IB is equal to <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/aaf11526d872f7b415b7e85cdd0aac82-.png" /> (A) 1 :4 (B) 1: 16 (C) 1: 2 (D) 1: 1

Tardigrade Admin · Accepted Answer

I propto a2 n2 ( I A / I B )=( a 12 n 12/ a 22 n 22) =((2/1))2 ×((1/2))2=1: 1

Q. The displacement-time graph for two sound waves A and B are shown in the figure, then the ratio of their intensities $I_{A} / I_{B}$ is equal to

$1 : 4$

$1 : 16$

$1 : 2$

$1 : 1$

$I \propto a^{2} n^{2}$
$\frac{I _{A}}{I _{B}} = \frac{a _{1}^{2} n _{1}^{2}}{a _{2}^{2} n _{2}^{2}}$
$= (\frac{2}{1})^{2} \times (\frac{1}{2})^{2} = 1 : 1$

Q. The displacement-time graph for two sound waves A and B are shown in the figure, then the ratio of their intensities IA​/IB​ is equal to

1:4

1:16

1:2

1:1