The disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency :

Question

The disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency : (A) 10 Hz (B) 360 Hz (C) 216 Hz (D) 60 Hz

Tardigrade Admin · Accepted Answer

Number of holes in the disk determines the number of waves produced on each rotation

= 60

The total number of waves per second determines the frequency of the sound.
So frequency

= 60 \times \frac{360}{60} = 360 Hz

Q. The disc of a siren containing 60 holes rotates at a constant speed of 360rpm. The emitted sound is in unison with a tuning fork of frequency :

10 Hz

360 Hz

216 Hz

60 Hz

Number of holes in the disk determines the number of waves produced on each rotation =60 The total number of waves per second determines the frequency of the sound. So frequency =60×60360​=360Hz

Q. The disc of a siren containing $60$ holes rotates at a constant speed of $360 r p m$ . The emitted sound is in unison with a tuning fork of frequency :

Number of holes in the disk determines the number of waves produced on each rotation $= 60$
The total number of waves per second determines the frequency of the sound.
So frequency $= 60 \times \frac{360}{60} = 360 Hz$