The dipole moment of the short bar magnet is 12.5 A-m2. The magnetic field on its axis at a distance of 0.5 m from the centre of the magnet is

Question

The dipole moment of the short bar magnet is 12.5 A-m2. The magnetic field on its axis at a distance of 0.5 m from the centre of the magnet is (A) 1.0 × 10Z-4 N/A-m (B) 4 × 10-2 N/A-m (C) 2 × 10-6 N/A-m (D) 6.64 × 10-8 N/A-m

Tardigrade Admin · Accepted Answer

The magnetic field, B = (μ0/4π). (2N/d3) = 10-7 ×(2×1.25/(0.5)3) = 2 ×10-6 NA-m

Q. The dipole moment of the short bar magnet is $12.5 A - m^{2}$ . The magnetic field on its axis at a distance of $0.5 m$ from the centre of the magnet is

$1.0 \times 10 Z^{- 4} N / A - m$

$4 \times 1 0^{- 2} N / A - m$

$2 \times 1 0^{- 6} N / A - m$

$6.64 \times 1 0^{- 8} N / A - m$

The magnetic field,
$B = \frac{μ _{0}}{4 π} . \frac{2 N}{d ^{3}}$
$= 1 0^{- 7} \times \frac{2 \times 1.25}{( 0.5 ) ^{3}}$
$= 2 \times 1 0^{- 6} N A - m$

Q. The dipole moment of the short bar magnet is 12.5A−m2. The magnetic field on its axis at a distance of 0.5m from the centre of the magnet is

1.0×10Z−4N/A−m

4×10−2N/A−m

2×10−6N/A−m

6.64×10−8N/A−m