Q.
The dimensions of μ0I/MB, where μ0 is the permeability of free space, I is the moment of inertia, M is the magnetic moment and B is the magnetic induction respectively, are those of
1904
184
Physical World, Units and Measurements
Report Error
Solution:
B=μ0ni (For a solenoid) where n is the number of turns per unit length, i is the current and μ0 is the permeability of free space.
or Bμ0=ni1 ∴[Bμ0]=[ni1] =[L−1][A]1=[LA−1] [M]=[ Magnetic moment ]=[m×2l]
=[ Pole strength × magnetic length ]
=[ weber × L]=[ML2T−2A−1×L]=[ML3T−2A−1] [I]=[ Moment of inertia ]=[ML2] ∴[BMμ0I] =[Bμ0]×[MI] =[LA−1]×[ML3T−2A−1][ML2] =[T2]=( time )2