The dimensions of electrical resistance are

Question

The dimensions of electrical resistance are (A) [M L2 T-2 A2] (B) [M L2 T-3 A-2] (C) [M L2 T-3 A2] (D) [M L2 T-2 A-2]

Tardigrade Admin · Accepted Answer

Electrical resistance R=( text Potential difference / text current (I)) =( text work done (W) / text charge (q)/ text current (I)) ∴ Dimensions of R=([M L2 T-2] /[A T]/[A]) =[M L2 T-3 A-2]

Q. The dimensions of electrical resistance are

$[M L^{2} T^{- 2} A^{2}]$

$[M L^{2} T^{- 3} A^{- 2}]$

$[M L^{2} T^{- 3} A^{2}]$

$[M L^{2} T^{- 2} A^{- 2}]$

Electrical resistance $R = \frac{Potential difference}{current ( I )}$
$= \frac{work done ( W ) / charge ( q )}{current ( I )}$
$∴$ Dimensions of $R = \frac{[ M L ^{2} T ^{- 2} ] / [ A T ]}{[ A ]}$
$= [M L^{2} T^{- 3} A^{- 2}]$

Q. The dimensions of electrical resistance are

[ML2T−2A2]

[ML2T−3A−2]

[ML2T−3A2]

[ML2T−2A−2]

Electrical resistance R= current (I) Potential difference ​ = current (I) work done (W)/ charge (q)​ ∴ Dimensions of R=[A][ML2T−2]/[AT]​ =[ML2T−3A−2]

$[M L^{2} T^{- 2} A^{2}]$

$[M L^{2} T^{- 3} A^{- 2}]$

$[M L^{2} T^{- 3} A^{2}]$

$[M L^{2} T^{- 2} A^{- 2}]$

Electrical resistance $R = \frac{Potential difference}{current ( I )}$
$= \frac{work done ( W ) / charge ( q )}{current ( I )}$
$∴$ Dimensions of $R = \frac{[ M L ^{2} T ^{- 2} ] / [ A T ]}{[ A ]}$
$= [M L^{2} T^{- 3} A^{- 2}]$