The dimensional formula of modulus of elasticity is

Question

The dimensional formula of modulus of elasticity is (A)  [ML-1T-2]  (B)  [M0LT-2]  (C)  [MLT-2]  (D)  [ML2T-2]

Tardigrade Admin · Accepted Answer

Modulus of elasticity =( text stress / text strain ) Stress =([F]/[A])=([ MLT -2]/[ L 2])=[ ML -1 T -2] Strain = dimensionless So, modulus of elasticity =[ ML -1 T -2]

Q. The dimensional formula of modulus of elasticity is

$[M L^{- 1} T^{- 2}]$

$[M^{0} L T^{- 2}]$

$[M L T^{- 2}]$

$[M L^{2} T^{- 2}]$

Modulus of elasticity $= \frac{stress}{strain}$
Stress $= \frac{[ F ]}{[ A ]} = \frac{[ M L T ^{- 2} ]}{[ L ^{2} ]} = [M L^{- 1} T^{- 2}]$
Strain $=$ dimensionless So, modulus of elasticity $= [M L^{- 1} T^{- 2}]$

Q. The dimensional formula of modulus of elasticity is

[ML−1T−2]

[M0LT−2]

[MLT−2]

[ML2T−2]

Modulus of elasticity = strain stress ​ Stress =[A][F]​=[L2][MLT−2]​=[ML−1T−2] Strain = dimensionless So, modulus of elasticity =[ML−1T−2]

$[M L^{- 1} T^{- 2}]$

$[M^{0} L T^{- 2}]$

$[M L T^{- 2}]$

$[M L^{2} T^{- 2}]$

Modulus of elasticity $= \frac{stress}{strain}$
Stress $= \frac{[ F ]}{[ A ]} = \frac{[ M L T ^{- 2} ]}{[ L ^{2} ]} = [M L^{- 1} T^{- 2}]$
Strain $=$ dimensionless So, modulus of elasticity $= [M L^{- 1} T^{- 2}]$