Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The differential equation of the family of parabolas with vertex at (0,-1) and having axis along the Y -axis is
Q. The differential equation of the family of parabolas with vertex at
(
0
,
−
1
)
and having axis along the
Y
-axis is
2004
177
EAMCET
EAMCET 2014
Report Error
A
y
y
′
+
2
x
y
+
1
=
0
B
x
y
′
+
y
+
1
=
0
C
x
y
′
−
2
y
−
2
=
0
D
x
y
′
−
y
−
1
=
0
Solution:
Equation of family of parabola having vertex
(
0
,
−
1
)
and axis along
y
-axis is
x
2
=
4
a
(
y
+
1
)
...
(
i
)
On differentiating both sides w.r.t.
x
, we get
2
x
=
4
a
y
′
⇒
a
=
2
y
′
x
On putting
a
=
2
y
′
1
in Eq. (i), we get
x
2
=
4
×
2
y
′
x
(
y
+
1
)
⇒
x
=
y
′
2
(
y
+
1
)
⇒
x
y
′
−
2
y
−
2
=
0