The differential equation of all circles of radius a is of order

Question

The differential equation of all circles of radius a is of order (A) 2 (B) 3 (C) 4 (D) none of these

Tardigrade Admin · Accepted Answer

The equation of the family of circles of radius a is (x - h)2 + (y - k)2 = a2 which is a two parameter family of curve. So its differential equation is of order two.

Q. The differential equation of all circles of radius $a$ is of order

$2$

$3$

$4$

none of these

The equation of the family of circles of radius a is $(x - h)^{2} + (y - k)^{2} = a^{2}$ which is a two parameter family of curve. So its differential equation is of order two.

Q. The differential equation of all circles of radius a is of order

2

3

4

none of these

The equation of the family of circles of radius a is (x−h)2+(y−k)2=a2 which is a two parameter family of curve. So its differential equation is of order two.

Q. The differential equation of all circles of radius $a$ is of order

$2$

$3$

$4$

The equation of the family of circles of radius a is $(x - h)^{2} + (y - k)^{2} = a^{2}$ which is a two parameter family of curve. So its differential equation is of order two.