The differential equation of all circles in the first quadrant which touch the coordinate axes is of order

Question

The differential equation of all circles in the first quadrant which touch the coordinate axes is of order (A) 1 (B) 2 (C) 3 (D) none of these

Tardigrade Admin · Accepted Answer

The equation of the family of circles which touch both the axes is (x - a)2 + (y - a)2 = a2, where a is a parameter. This is one parameter family of curve. So its differential equation is of order one.

Q. The differential equation of all circles in the first quadrant which touch the coordinate axes is of order

$1$

$2$

$3$

none of these

The equation of the family of circles which touch both the axes is $(x - a)^{2} + (y - a)^{2} = a^{2}$ , where $a$ is a parameter. This is one parameter family of curve. So its differential equation is of order one.

Q. The differential equation of all circles in the first quadrant which touch the coordinate axes is of order

1

2

3

none of these

The equation of the family of circles which touch both the axes is (x−a)2+(y−a)2=a2, where a is a parameter. This is one parameter family of curve. So its differential equation is of order one.

$1$

$2$

$3$

The equation of the family of circles which touch both the axes is $(x - a)^{2} + (y - a)^{2} = a^{2}$ , where $a$ is a parameter. This is one parameter family of curve. So its differential equation is of order one.