The difference in angular momentum associated with the electron in the two successive orbits of hydrogen atom is

Question

The difference in angular momentum associated with the electron in the two successive orbits of hydrogen atom is (A) (h/π) (B) (h/2π) (C) (h/2) (D) (n-1)(h/2π)

Tardigrade Admin · Accepted Answer

Ln = nh / 2 π. Hence Ln + 1 - Ln = h/2 π .

Q. The difference in angular momentum associated with the electron in the two successive orbits of hydrogen atom is

$\frac{h}{π}$

$\frac{h}{2 π}$

$\frac{h}{2}$

$(n - 1)$ $\frac{h}{2 π}$

$L_{n} = nh /2 π$ . Hence $L_{n + 1} - L_{n} = h /2 π$ .

Q. The difference in angular momentum associated with the electron in the two successive orbits of hydrogen atom is

πh​

2πh​

2h​

(n−1)2πh​

Ln​=nh/2π. Hence Ln+1​−Ln​=h/2π.

$\frac{h}{π}$

$\frac{h}{2 π}$

$\frac{h}{2}$

$(n - 1)$ $\frac{h}{2 π}$

$L_{n} = nh /2 π$ . Hence $L_{n + 1} - L_{n} = h /2 π$ .