The density of a material in SI units is 128 kg m-3. In certain units in which the unit of length is 25 cm and the unit of mass is 50 g, the numerical value of density of the material is :

Question

The density of a material in SI units is 128 kg m-3. In certain units in which the unit of length is 25 cm and the unit of mass is 50 g, the numerical value of density of the material is : (A) 410 (B) 640 (C) 16 (D) 40

Tardigrade Admin · Accepted Answer

(128 kg/m3) = (125 (50g)(20)/(25cm)3(4)3) = (128/64) (20)units = 40 units

Q. The density of a material in SI units is $128 k g m^{- 3}$ . In certain units in which the unit of length is $25 c m$ and the unit of mass is $50 g$ , the numerical value of density of the material is :

410

640

16

40

$\frac{128 k g}{m ^{3}} = \frac{125 ( 50 g ) ( 20 )}{( 25 c m ) ^{3} ( 4 ) ^{3}}$
$= \frac{128}{64} (20) u ni t s$
$= 40 u ni t s$

Q. The density of a material in SI units is 128kgm−3. In certain units in which the unit of length is 25cm and the unit of mass is 50g, the numerical value of density of the material is :

410

640

16

40

m3128kg​=(25cm)3(4)3125(50g)(20)​ =64128​(20)units =40units

Q. The density of a material in SI units is $128 k g m^{- 3}$ . In certain units in which the unit of length is $25 c m$ and the unit of mass is $50 g$ , the numerical value of density of the material is :

$\frac{128 k g}{m ^{3}} = \frac{125 ( 50 g ) ( 20 )}{( 25 c m ) ^{3} ( 4 ) ^{3}}$
$= \frac{128}{64} (20) u ni t s$
$= 40 u ni t s$