The density of a material in SI unit is 128 kg m-3 . In certain units in which the unit of length is 25 cm and the unit of mass is 50 g, the numerical value of density of the material is:

Question

The density of a material in SI unit is 128 kg m-3 . In certain units in which the unit of length is 25 cm and the unit of mass is 50 g, the numerical value of density of the material is: (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Density of material in SI unit, = (128 kg/m3) Density of material in new system = (128(50g) (20)/(25 cm)3 (4)3) = (128/64) × (20) = 40 Unit

Q. The density of a material in $S I$ unit is $128 k g m^{- 3}$ . In certain units in which the unit of length is $25 c m$ and the unit of mass is $50 g$ , the numerical value of density of the material is:

Density of material in $S I$ unit,
$= \frac{128 k g}{m ^{3}}$
Density of material in new system
$= \frac{128 ( 50 g ) ( 20 )}{( 25 c m ) ^{3} ( 4 ) ^{3}}$
$= \frac{128}{64} \times (20) = 40$ Unit

Q. The density of a material in SI unit is 128kgm−3 . In certain units in which the unit of length is 25cm and the unit of mass is 50g, the numerical value of density of the material is:

Density of material in SI unit, =m3128kg​ Density of material in new system =(25cm)3(4)3128(50g)(20)​ =64128​×(20)=40 Unit

Q. The density of a material in $S I$ unit is $128 k g m^{- 3}$ . In certain units in which the unit of length is $25 c m$ and the unit of mass is $50 g$ , the numerical value of density of the material is:

Density of material in $S I$ unit,
$= \frac{128 k g}{m ^{3}}$
Density of material in new system
$= \frac{128 ( 50 g ) ( 20 )}{( 25 c m ) ^{3} ( 4 ) ^{3}}$
$= \frac{128}{64} \times (20) = 40$ Unit