Question

The $\Delta G^{\circ }$ for the reaction $=+57kJ$
$M{X}_{(s)}\rightleftharpoons M_{(aq)}^{+}+X_{(aq)}^{-}$
Hence $K_{sp}$ for the reaction is

• A. $10^{-5}$
• B. $10^{-6}$
• C. $10^{-10}$
• D. $10^{-16}$

Answer 1

Answer: (C)

$\Delta G^{\circ }=-2.303\times 8.31\times 298\log K_{sp}$

$\Rightarrow \log K_{sp}=\frac{-57000}{2.303\times 8.31\times 298}$

On solving we get $K_{sp}\simeq 10^{-10}$