The degree of dissociation of SO3 at equilibrium pressure is: Kp for 2SO3 (g) leftharpoons 2SO2 (g) + O2 (g)

Question

The degree of dissociation of SO3 at equilibrium pressure is: Kp for 2SO3 (g) leftharpoons 2SO2 (g) + O2 (g) (A) [(P0α3)/2(1 - α)3] (B) [(P0α3)/(2 +α)(1 -α )2] (C) [(P0α2)/2 (1 - α )2] (D) none of these

Tardigrade Admin · Accepted Answer

2SO3 leftharpoons 2SO2 + O2 P(1- α) Pα (Pα/2) P[1+(α/2)]=Po KP = ((P2α2)(P (α/2))/p2(1-α2))=(Poα3/(2+α)(1-α)2)

Q. The degree of dissociation of $S O_{3}$ at equilibrium pressure is:
$K_{p}$ for $2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$

$[(P_{0} α^{3}) /2 (1 - α)^{3}]$

$[(P_{0} α^{3}) / (2 + α) (1 - α)^{2}]$

$[(P_{0} α^{2}) /2 (1 - α)^{2}]$

none of these

$2 S O_{3} ⇌ 2 S O_{2} + O_{2}$
$P (1 - α) P α \frac{P α}{2}$
$P [1 + \frac{α}{2}] = P_{o}$
$K_{P} = \frac{( P ^{2} α ^{2} ) ( P \frac{α}{2} )}{p ^{2} ( 1 - α ^{2} )} = \frac{P _{o} α ^{3}}{( 2 + α ) ( 1 - α ) ^{2}}$

Q. The degree of dissociation of SO3​ at equilibrium pressure is: Kp​ for 2SO3​(g)⇌2SO2​(g)+O2​(g)

[(P0​α3)/2(1−α)3]

[(P0​α3)/(2+α)(1−α)2]

[(P0​α2)/2(1−α)2]