The de Broglie wavelength of an electron moving with kinetic energy of 144 eV is nearly

Question

The de Broglie wavelength of an electron moving with kinetic energy of 144 eV is nearly (A) 102 × 10-3 nm (B) 102 × 10-4 nm (C) 102 × 10-5 nm (D) 102 × 10-2 nm

Tardigrade Admin · Accepted Answer

λ=(12.27/√V) mathringA =(12.27/√144)×1010 =1.02×10-10 m =102×10-3 nm

Q. The de Broglie wavelength of an electron moving with kinetic energy of $144 e V$ is nearly

$102 \times 1 0^{- 3} nm$

$102 \times 1 0^{- 4} nm$

$102 \times 1 0^{- 5} nm$

$102 \times 1 0^{- 2} nm$

$λ = \frac{12.27}{V} \overset{˚}{A}$
$= \frac{12.27}{144} \times 1 0^{10}$
$= 1.02 \times 1 0^{- 10} m$
$= 102 \times 1 0^{- 3} nm$

Q. The de Broglie wavelength of an electron moving with kinetic energy of 144eV is nearly

102×10−3nm

102×10−4nm

102×10−5nm

102×10−2nm