Question

The de Broglie wavelength of an electron in the $4^{th}$ Bohr orbit is :

• A. $6\pi a_0$
• B. $2\pi a_0$
• C. $8\pi a_0$
• D. $4\pi a_0$

Answer 1

Answer: (C)

$2\pi r=n\lambda$
$forn=1,r=a_0$
$n=4,r=16a_0$
$So,2\pi \times 16a_0=4\times \lambda$
$\lambda =8\pi a_0$