The de-Broglie wavelength of a particle with mass 1 g and velocity 100 m/s is

Question

The de-Broglie wavelength of a particle with mass 1 g and velocity 100 m/s is (A) 6.63 × 10-33 m (B) 6.63 × 10-34 m (C) 6.63 × 10-35 m (D) 6.63 × 10-36 m

Tardigrade Admin · Accepted Answer

p=(h/λ) (de-Broglie equation) λ=(h/mv)(∵ p=mv) h = 6.625 × 10-34 ≈ 6.63 × 10-34 kg/s λ=(6.63 ×10-34 kg m2/ s/10-10 kg × 100 m/s) =6.63 ×10-33 m

Q. The de-Broglie wavelength of a particle with mass $1 g$ and velocity $100 m / s$ is

$6.63 \times 1 0^{- 33} m$

$6.63 \times 1 0^{- 34} m$

$6.63 \times 1 0^{- 35} m$

$6.63 \times 1 0^{- 36} m$

$p = \frac{h}{λ}$ (de-Broglie equation)
$λ = \frac{h}{m v} (∵ p = m v)$
$h = 6.625 \times 1 0^{- 34}$
$\approx 6.63 \times 1 0^{- 34} k g / s$
$λ = \frac{6.63 \times 1 0 ^{- 34} k g m ^{2} / s}{1 0 ^{- 10} k g \times 100 m / s}$
$= 6.63 \times 1 0^{- 33} m$

Q. The de-Broglie wavelength of a particle with mass 1g and velocity 100m/s is

6.63×10−33m

6.63×10−34m

6.63×10−35m

6.63×10−36m