The de-Broglie wavelength λ associated with an electron having kinetic energy E is given by the expression

Question

The de-Broglie wavelength λ associated with an electron having kinetic energy E is given by the expression (A) (h/√2 m E) (B) (2 h/m E) (C) 2 mhE (D) (2 √2 m E/h)

Tardigrade Admin · Accepted Answer

(1/2) m v2=E ⇒ m v=√2 m E; ∴ E=(h/m v)=(h/√2 m E)

Q. The de-Broglie wavelength $λ$ associated with an electron having kinetic energy $E$ is given by the expression

$\frac{h}{2 m E}$

$\frac{2 h}{m E}$

$2 mh E$

$\frac{2 2 m E}{h}$

$\frac{1}{2} m v^{2} = E$
$\Rightarrow m v = 2 m E;$
$∴ E = \frac{h}{m v} = \frac{h}{2 m E}$

Q. The de-Broglie wavelength λ associated with an electron having kinetic energy E is given by the expression

2mE​h​

mE2h​

2mhE

h22mE​​