Given x=t2+2t−1&y=3t+5 ⇒x=t2+2t+1−2&y=3t+3+2 ⇒x=(t+1)2−2&y=3(t+1)+2(2) ⇒(t+1)=x+2 .......... (1) ∴ Equation (2) becomes [using equation (1)] y=3x+2+2 ⇒y−2=3x+2
squaring both sides, we get (y−2)2=9(x+2) ⇒Y2=9X where Y=y−2&X=x+2
This equation represents a parabola