The current I through 10 Ω resistor in the circuit given below is

Question

The current I through 10 Ω resistor in the circuit given below is (A) 50 mA (B) 20 mA (C) 40 mA (D) 80 mA

Tardigrade Admin · Accepted Answer

Here, diode D2 is reverse biased while D1 is forward biased. So, no current flows across D2, current flows through diode D1 I=(V/R)=(2/10+15)=(2/25) =0.08A=80 mA

Q. The current $I$ through $10 Ω$ resistor in the circuit given below is

$50 m A$

$20 m A$

$40 m A$

$80 m A$

$35 m A$

Here, diode $D_{2}$ is reverse biased while $D_{1}$ is forward biased. So, no current flows across $D_{2},$ current flows through diode $D_{1}$
$I = \frac{V}{R} = \frac{2}{10 + 15} = \frac{2}{25}$
$= 0.08 A = 80 m A$

Q. The current I through 10Ω resistor in the circuit given below is

50mA

20mA

40mA

80mA

35mA

Here, diode D2​ is reverse biased while D1​ is forward biased. So, no current flows across D2​, current flows through diode D1​ I=RV​=10+152​=252​ =0.08A=80mA