The current flowing through 10 Ω resistor in the circuit shown in the figure is

Question

The current flowing through 10 Ω resistor in the circuit shown in the figure is (A) 50 mA (B) 20 mA (C) 40 mA (D) 80 mA

Tardigrade Admin · Accepted Answer

In the given circuit, junction diode D1 is forward biased and will conduct whereas junction diode D2 is reverse biased and will not conduct. Therefore current through 10 Ω resistor is I = (2 V/10 Ω+15 Ω) = 0.08 A = 80 mA

Q. The current flowing through $10 Ω$ resistor in the circuit shown in the figure is

50 mA

20 mA

40 mA

80 mA

In the given circuit, junction diode $D_{1}$ is forward biased and will conduct whereas junction diode $D_{2}$ is reverse biased and will not conduct. Therefore current through $10 Ω$ resistor is
$I = \frac{2 V}{10 Ω + 15 Ω} = 0.08 A = 80 m A$

Q. The current flowing through 10Ω resistor in the circuit shown in the figure is