The correct statement with regard to H 2+and H 2-is

Question

The correct statement with regard to H 2+and H 2-is (A) Both H 2+and H 2-do not exist (B) H 2 -is more stable than H 2 + (C) H 2 +is more stable than H 2 - (D) Both H 2+and H 2-are equally stable

Tardigrade Admin · Accepted Answer

The electron presence in anti-bonding orbital result in repulsion and decrease of stability The stability order follows the molecular orbital theory The formula for bonding order can be regarded as follows
Bonding order

= \frac{1}{2}

(Number of bonding electrons -Number of antibonding electrons)
The number of antibonding electrons in

H_{2}^{+}

is

0

The number of antibonding electrons in

H_{2}^{-}

is

1

The bonding order of

H_{2}^{+}

is

= \frac{1}{2} (1 - 0) = 0.5

The bonding order of

H_{2}^{-}

is

= \frac{1}{2} (2 - 1) = 0.5

H_{2}^{+}

and

H_{2}^{-}

molecule have the same bond order
Presence of anti-bonding electron decreases the stability of the molecule Therefore,

H_{2}^{+}

is more stable than

H_{2}^{-}

Q. The correct statement with regard to $H_{2}^{+}$ and $H_{2}^{-}$ is

Both $H_{2}^{+}$ and $H_{2}^{-}$ do not exist

$H_{2}^{-}$ is more stable than $H_{2}^{+}$

$H_{2}^{+}$ is more stable than $H_{2}^{-}$

Both $H_{2}^{+}$ and $H_{2}^{-}$ are equally stable

Q. The correct statement with regard to H2+​and H2−​is

Both H2+​and H2−​do not exist

H2​−is more stable than H2​+

H2​+is more stable than H2​−

Both H2+​and H2−​are equally stable

Q. The correct statement with regard to $H_{2}^{+}$ and $H_{2}^{-}$ is

Both $H_{2}^{+}$ and $H_{2}^{-}$ do not exist

$H_{2}^{-}$ is more stable than $H_{2}^{+}$

$H_{2}^{+}$ is more stable than $H_{2}^{-}$

Both $H_{2}^{+}$ and $H_{2}^{-}$ are equally stable