The correct order of N-compounds in its decreasing order of oxidation states is

Question

The correct order of N-compounds in its decreasing order of oxidation states is (A) HNO3,NH4Cl,NO,N2 (B) HNO3,NO,NH4Cl,N2 (C) HNO3,NO,N2,NH4Cl (D) NH4Cl,N2,NO,HNO3

Tardigrade Admin · Accepted Answer

The oxidation number of N-atoms in these molecules is as follows overset+ 5H N O3, overset+ 2N O, overset0N2, overset- 3N H4 C l

Q. The correct order of N-compounds in its decreasing order of oxidation states is

$H N O_{3}, N H_{4} Cl, NO, N_{2}$

$H N O_{3}, NO, N H_{4} Cl, N_{2}$

$H N O_{3}, NO, N_{2}, N H_{4} Cl$

$N H_{4} Cl, N_{2}, NO, H N O_{3}$

The oxidation number of N-atoms in these molecules is as follows

$H N O_{3} + 5, NO + 2, N_{2} 0, N H_{4} Cl - 3$

Q. The correct order of N-compounds in its decreasing order of oxidation states is

HNO3​,NH4​Cl,NO,N2​

HNO3​,NO,NH4​Cl,N2​

HNO3​,NO,N2​,NH4​Cl

NH4​Cl,N2​,NO,HNO3​

The oxidation number of N-atoms in these molecules is as follows HNO3​+5​,NO+2,N2​0​,NH4​Cl−3​

$H N O_{3}, N H_{4} Cl, NO, N_{2}$

$H N O_{3}, NO, N H_{4} Cl, N_{2}$

$H N O_{3}, NO, N_{2}, N H_{4} Cl$

$N H_{4} Cl, N_{2}, NO, H N O_{3}$

The oxidation number of N-atoms in these molecules is as follows

$H N O_{3} + 5, NO + 2, N_{2} 0, N H_{4} Cl - 3$