The correct order of increasing [ H 3 O +] in the following aqueous solutions is

Question

The correct order of increasing [ H 3 O +] in the following aqueous solutions is (A) 0.01 M H 2 S <0.01 M H 2 SO 4<0.01 M NaCl <0.01 M NaNO 2 (B) 0.01 M NaCl <0.01 M NaNO 2<0.01 M H 2 S <0.01 M H 2 SO 4 (C) 0.01 M NaNO 2 < 0.01 M NaCl < 0.01 MH 2 S <0.01 M H 2 SO 4 (D) 0.01 MH 2 S < 0.01 M NaNO 2 < 0.01 M NaCl < 0.01 M H 2 SO 4

Tardigrade Admin · Accepted Answer

H 2 SO 4 is strong acid having pH < 7 . NaNO 2 on hydrolysis gives alkaline solution of pH >7 NaCl is neutral and H 2 S is weak acid.

Q. The correct order of increasing $[H_{3} O^{+}]$ in the following aqueous solutions is

$0.01 M H_{2} S < 0.01 M H_{2} S O_{4} < 0.01 M N a Cl$ $< 0.01 M N a N O_{2}$

$0.01 M N a Cl < 0.01 M N a N O_{2} < 0.01 M H_{2} S$ $< 0.01 M H_{2} S O_{4}$

$0.01 M N a N O_{2} < 0.01 M N a Cl < 0.01 M H_{2} S$ $< 0.01 M H_{2} S O_{4}$

$0.01 M H_{2} S < 0.01 M N a N O_{2} < 0.01 M N a Cl$ $< 0.01 M H_{2} S O_{4}$

$H_{2} S O_{4}$ is strong acid having $p H < 7. N a N O_{2}$ on hydrolysis gives alkaline solution of $p H > 7 N a Cl$ is neutral and $H_{2} S$ is weak acid.

Q. The correct order of increasing [H3​O+] in the following aqueous solutions is

0.01MH2​S<0.01MH2​SO4​<0.01MNaCl <0.01MNaNO2​

0.01MNaCl<0.01MNaNO2​<0.01MH2​S <0.01MH2​SO4​

0.01MNaNO2​<0.01MNaCl<0.01MH2​S <0.01MH2​SO4​

0.01MH2​S<0.01MNaNO2​<0.01MNaCl <0.01MH2​SO4​