The correct order of dipole moments of HF , H 2 S and H 2 O is

Question

The correct order of dipole moments of HF , H 2 S and H 2 O is (A) HF < H 2 S < H 2 O (B) HF < H 2 S > H 2 O (C) HF > H 2 S > H 2 O (D) HF > H 2 O < H 2 S

Tardigrade Admin · Accepted Answer

H - F μ=1.91 D H 2 O (θ=104.5°)=1.84 D H 2 S (θ=92°)=1.88 D

Q. The correct order of dipole moments of $H F, H_{2} S$ and $H_{2} O$ is

$H F < H_{2} S < H_{2} O$

$H F < H_{2} S > H_{2} O$

$H F > H_{2} S > H_{2} O$

$H F > H_{2} O < H_{2} S$

$H - F μ = 1.91 D$
$H_{2} O (θ = 104. 5^{\circ}) = 1.84 D$
$H_{2} S (θ = 9 2^{\circ}) = 1.88 D$

Q. The correct order of dipole moments of HF,H2​S and H2​O is

HF<H2​S<H2​O

HF<H2​S>H2​O

HF>H2​S>H2​O

HF>H2​O<H2​S