The correct order of bond angle of NO 2+, NO 2 and NO 2-is

Question

The correct order of bond angle of NO 2+, NO 2 and NO 2-is (A) NO 2+< NO 2< NO 2- (B) NO 2+= NO 2-< NO 2 (C) NO 2+> NO 2-> NO 2 (D) NO 2+> NO 2< NO 2-

Tardigrade Admin · Accepted Answer

Correct answer is (c) NO 2+> NO 2-> NO 2

Q. The correct order of bond angle of $N O_{2}^{+}, N O_{2}$ and $N O_{2}^{-}$ is

$N O_{2}^{+} < N O_{2} < N O_{2}^{-}$

$N O_{2}^{+} = N O_{2}^{-} < N O_{2}$

$N O_{2}^{2} > N O_{2}^{2} > N O_{2}^{2}$

$N O_{2}^{+} > N O_{2} < N O_{2}^{-}$

Correct answer is (c) $N O_{2}^{2} > N O_{2}^{2} > N O_{2}^{2}$

Q. The correct order of bond angle of NO2+​,NO2​ and NO2−​is

NO2+​<NO2​<NO2−​

NO2+​=NO2−​<NO2​

NO22​>NO22​>NO22​

NO2+​>NO2​<NO2−​

Correct answer is (c) NO22​>NO22​>NO22​

Q. The correct order of bond angle of $N O_{2}^{+}, N O_{2}$ and $N O_{2}^{-}$ is

$N O_{2}^{+} < N O_{2} < N O_{2}^{-}$

$N O_{2}^{+} = N O_{2}^{-} < N O_{2}$

$N O_{2}^{2} > N O_{2}^{2} > N O_{2}^{2}$

$N O_{2}^{+} > N O_{2} < N O_{2}^{-}$

Correct answer is (c) $N O_{2}^{2} > N O_{2}^{2} > N O_{2}^{2}$