Question

The correct hybridization of $Fe$ in complex ${\mathrm{K}}_3\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]$ is

• A. $ds{p}^3$
• B. $s{p}^3$
• C. $s{p}^3{d}^2$
• D. $d^{2}s{p}^3$

Answer 1

Answer: (D)

$K_3\left[Fe(CN{)}_6\right]$

Electronic configuration of $Fe=[Ar]4s^{2}3d^6$

Electronic configuration of $F{e}^{+3}=[Ar]3d^5$

Number of ligand (coordination numbr) $=6$

Nature of ligand is strong field.



Hybridization of $Fe$ is $d^{2}s{p}^3$ .