The correct descending order of oxidizing power of the following is

Question

The correct descending order of oxidizing power of the following is (A)  Cr2O72- > MnO4- > VO2+ (B)  MnO4- > Cr2O72- > VO2+ (C)  VO2+ > MnO4- > Cr2O72-  (D)  MnO4- > VO2+ > Cr2O72-

Tardigrade Admin · Accepted Answer

Oxidising power depends upon the stability of reduction product optained. Since lower oxides of Mn are more stable than that of C r and V, so the order of oxidising power is MnO 4-> Cr 2 O 72-> VO 2+

Q. The correct descending order of oxidizing power of the following is

$C r_{2} O_{7}^{2 -} > M n O_{4}^{-} > V O_{2}^{+}$

$M n O_{4}^{-} > C r_{2} O_{7}^{2 -} > V O_{2}^{+}$

$V O_{2}^{+} > M n O_{4}^{-} > C r_{2} O_{7}^{2 -}$

$M n O_{4}^{-} > V O_{2}^{+} > C r_{2} O_{7}^{2 -}$

$C r_{2} O_{7}^{2 -} > V O_{2}^{+} > M n O_{4}^{-}$

Oxidising power depends upon the stability of reduction product optained. Since lower oxides of $M n$ are more stable than that of $C r$ and $V$ , so the order of oxidising power is

$M n O_{4}^{-} > C r_{2} O_{7}^{2 -} > V O_{2}^{+}$

Q. The correct descending order of oxidizing power of the following is

Cr2​O72−​>MnO4−​>VO2+​

MnO4−​>Cr2​O72−​>VO2+​

VO2+​>MnO4−​>Cr2​O72−​

MnO4−​>VO2+​>Cr2​O72−​

Cr2​O72−​>VO2+​>MnO4−​