The correct conversion of the following into basic units. (i) 28.7 pm (ii) 15.15 μ s (iii) 25365 mg

Question

The correct conversion of the following into basic units. (i) 28.7 pm (ii) 15.15 μ s (iii) 25365 mg (A) (i) arrow 28.7 × 10-11 m, (ii) arrow 1.515 × 10-6 s, (iii) arrow 2.5365 × 10-3 kg (B) (i) arrow 2.87 × 10-11 m, (ii) arrow 1.515 × 10-5 s, (iii) arrow 2.5365 × 10-2 kg (C) (i) arrow 2.87 × 10-10 m, (ii) arrow 1.515 × 10-5 s, (iii) arrow 2.5365 × 10-3 kg (D) (i) arrow 2.87 × 10-10 m, (ii) arrow 1.515 × 10-6 s, (iii) arrow 2.5365 × 10-2 kg

Tardigrade Admin · Accepted Answer

(i) 28.7 pm × (10-12 m /1 pm )=2.87 × 10-11 m (ii) 15.15 μ s × (10-6 s /1 μ s )=1.515 × 10-5 s (iii) 25365 mg × (1 g /1000 mg ) × (1 kg /1000 g ) =2.5365 × 10-2 kg

Q. The correct conversion of the following into basic units.
(i) $28.7 p m$
(ii) $15.15 μ s$
(iii) $25365 m g$

(i) $\to 28.7 \times 1 0^{- 11} m$ , (ii) $\to 1.515 \times 1 0^{- 6} s$ , (iii) $\to 2.5365 \times 1 0^{- 3} k g$

(i) $\to 2.87 \times 1 0^{- 11} m$ , (ii) $\to 1.515 \times 1 0^{- 5} s$ , (iii) $\to 2.5365 \times 1 0^{- 2} k g$

(i) $\to 2.87 \times 1 0^{- 10} m$ , (ii) $\to 1.515 \times 1 0^{- 5} s$ , (iii) $\to 2.5365 \times 1 0^{- 3} k g$

(i) $\to 2.87 \times 1 0^{- 10} m$ , (ii) $\to 1.515 \times 1 0^{- 6} s$ , (iii) $\to 2.5365 \times 1 0^{- 2} k g$

(i) $28.7 p m \times \frac{1 0 ^{- 12} m}{1 p m} = 2.87 \times 1 0^{- 11} m$
(ii) $15.15 μ s \times \frac{1 0 ^{- 6} s}{1 μ s} = 1.515 \times 1 0^{- 5} s$
(iii) $25365 m g \times \frac{1 g}{1000 m g} \times \frac{1 k g}{1000 g}$ $= 2.5365 \times 1 0^{- 2} k g$

Q. The correct conversion of the following into basic units. (i) 28.7pm (ii) 15.15μs (iii) 25365mg

(i) →28.7×10−11m, (ii) →1.515×10−6s, (iii) →2.5365×10−3kg

(i) →2.87×10−11m, (ii) →1.515×10−5s, (iii) →2.5365×10−2kg

(i) →2.87×10−10m, (ii) →1.515×10−5s, (iii) →2.5365×10−3kg

(i) →2.87×10−10m, (ii) →1.515×10−6s, (iii) →2.5365×10−2kg