The correct Biot-Savart law in vector form is

Question

The correct Biot-Savart law in vector form is (A) d vecB = (μ0/4 π) (I(d vecl × vecr )/r2)  (B) d vecB = (μ0/4 π) (I(d vecl × vecr )/r3) (C) d vecB = (μ0/4 π) (I d vecl /r2)  (D) d vecB = (μ0/4 π) (I d vecl /r3)

Tardigrade Admin · Accepted Answer

Biot-Savart law in vector form is dB = (μ0/4π) (I dl × vecr/r3)

Q. The correct Biot-Savart law in vector form is

$d B = \frac{μ _{0}}{4 π} \frac{I ( d l \times r )}{r ^{2}}$

$d B = \frac{μ _{0}}{4 π} \frac{I ( d l \times r )}{r ^{3}}$

$d B = \frac{μ _{0}}{4 π} \frac{I d l}{r ^{2}}$

$d B = \frac{μ _{0}}{4 π} \frac{I d l}{r ^{3}}$

Biot-Savart law in vector form is
$d B = \frac{μ _{0}}{4 π} \frac{I d l \times r}{r ^{3}}$

Q. The correct Biot-Savart law in vector form is

dB=4πμ0​​r2I(dl×r)​

dB=4πμ0​​r3I(dl×r)​

dB=4πμ0​​r2Idl​

dB=4πμ0​​r3Idl​

Biot-Savart law in vector form is dB=4πμ0​​r3Idl×r​

$d B = \frac{μ _{0}}{4 π} \frac{I ( d l \times r )}{r ^{2}}$

$d B = \frac{μ _{0}}{4 π} \frac{I ( d l \times r )}{r ^{3}}$

$d B = \frac{μ _{0}}{4 π} \frac{I d l}{r ^{2}}$

$d B = \frac{μ _{0}}{4 π} \frac{I d l}{r ^{3}}$

Biot-Savart law in vector form is
$d B = \frac{μ _{0}}{4 π} \frac{I d l \times r}{r ^{3}}$