The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is.

Question

The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is. (A) (i) SOCl 2 (ii) KCN (iii) H 2 / Ni , Na ( Hg ) / C 2 H 5 OH (B) (i) HCl (ii) H 2 / Ni , Na ( Hg ) / C 2 H 5 OH (C) (i) SOCl 2 (ii) KCN (iii) CH 3 NH 2 (D) (i) HCl (ii) CH 3 NH 2

Tardigrade Admin · Accepted Answer

Correct answer is (a) (i) SOCl 2 (ii) KCN (iii) H 2 / Ni , Na ( Hg ) / C 2 H 5 OH

Q. The conversion of propan- $1$ -ol to $n$ -butylamine involves the sequential addition of reagents. The correct sequential order of reagents is.

(i) $SOC l_{2}$ (ii) $K CN$ (iii) $H_{2} / N i, N a (H g) / C_{2} H_{5} O H$

(i) $H Cl$ (ii) $H_{2} / N i, N a (H g) / C_{2} H_{5} O H$

(i) $SOC l_{2}$ (ii) $K CN$ (iii) $C H_{3} N H_{2}$

(i) $H Cl$ (ii) $C H_{3} N H_{2}$

Correct answer is (a) (i) $SOC l_{2}$ (ii) $K CN$ (iii) $H_{2} / N i, N a (H g) / C_{2} H_{5} O H$

Q. The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is.

(i) SOCl2​ (ii) KCN (iii) H2​/Ni,Na(Hg)/C2​H5​OH

(i) HCl (ii) H2​/Ni,Na(Hg)/C2​H5​OH

(i) SOCl2​ (ii) KCN (iii) CH3​NH2​

(i) HCl (ii) CH3​NH2​