The conect order of H - N - H bond angles of ammonia, ammonium ion and amide are

Question

The conect order of H - N - H bond angles of ammonia, ammonium ion and amide are (A) NH 2-> NH 3> NH 4+ (B) NH 4+> NH 3> NH 2- (C) NH 3> NH 2-> NH 4+ (D) NH 3> NH 4+> NH 2-

Tardigrade Admin · Accepted Answer

According to VSEPR theory repulsion between :
Lone pair-lone pair

>

Lone pair-bond pair

>

Bond pair-bond pair
As the repulsion is increases then bond angle is decreases.

Molecule	Lone pair	Bond pair	Bond angle
$N H_{2}^{-}$	2	2	$10 5^{\circ}$
$N H_{3}$	1	3	$10 7^{\circ}$
$N H_{4}^{+}$	0	4	$10 9^{\circ} 2 8^{'}$

Therefore, the order of bond angle is

N H_{4}^{+} > N H_{3} > N H_{2}^{-}

Q. The conect order of $H - N - H$ bond angles of ammonia, ammonium ion and amide are

$N H_{2}^{-} > N H_{3} > N H_{4}^{+}$

$N H_{4}^{+} > N H_{3} > N H_{2}^{-}$

$N H_{3} > N H_{2}^{-} > N H_{4}^{+}$

$N H_{3} > N H_{4}^{+} > N H_{2}^{-}$

Q. The conect order of H−N−H bond angles of ammonia, ammonium ion and amide are

NH2−​>NH3​>NH4+​

NH4+​>NH3​>NH2−​

NH3​>NH2−​>NH4+​

NH3​>NH4+​>NH2−​

Q. The conect order of $H - N - H$ bond angles of ammonia, ammonium ion and amide are

$N H_{2}^{-} > N H_{3} > N H_{4}^{+}$

$N H_{4}^{+} > N H_{3} > N H_{2}^{-}$

$N H_{3} > N H_{2}^{-} > N H_{4}^{+}$

$N H_{3} > N H_{4}^{+} > N H_{2}^{-}$