The conductivity of a saturated solution of BaSO4 is 3.06 × 10-6 ohm-1 cm-1 and its equivalent conductance is 1.53 ohm-1 cm-1 textequivalent-1 The Ksp of the BaSO4 will be

Question

The conductivity of a saturated solution of BaSO4 is 3.06 × 10-6 ohm-1 cm-1 and its equivalent conductance is 1.53 ohm-1 cm-1 textequivalent-1 The Ksp of the BaSO4 will be (A) 4 × 10-12 (B) 2.5 × 10-9 (C) 2.5 × 10-13 (D) 4 × 10-6

Tardigrade Admin · Accepted Answer

λm=(1000 K/S) =(1000×3.06×10-6/S)=1.53 S=2×10-3 ( textmol/ textlitre) Ksp(BaSO4)=S2=(2×10-3)2=4×10-6

Q. The conductivity of a saturated solution of $B a S O_{4}$ is $3.06 \times 1 0^{- 6} o h m^{- 1} c m^{- 1}$ and its equivalent conductance is $1.53 o h m^{- 1} c m^{- 1}$ $equivalent^{- 1}$ The $K_{s p}$ of the $B a S O_{4}$ will be

$4 \times 1 0^{- 12}$

$2.5 \times 1 0^{- 9}$

$2.5 \times 1 0^{- 13}$

$4 \times 1 0^{- 6}$

$λ_{m} = \frac{1000 K}{S}$
$= \frac{1000 \times 3.06 \times 1 0 ^{- 6}}{S} = 1.53$
$S = 2 \times 1 0^{- 3} \frac{mol}{litre}$
$K_{s p (B a S O_{4})} = S_{2} = (2 \times 1 0^{- 3})^{2} = 4 \times 1 0^{- 6}$

Q. The conductivity of a saturated solution of BaSO4​ is 3.06×10−6ohm−1cm−1 and its equivalent conductance is 1.53ohm−1cm−1 equivalent−1 The Ksp​ of the BaSO4​ will be

4×10−12

2.5×10−9

2.5×10−13

4×10−6