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Question
Mathematics
The condition f(x)=x3+p x2+q x+ r(x ∈ R) to have no extreme value, is
Q. The condition
f
(
x
)
=
x
3
+
p
x
2
+
q
x
+
r
(
x
∈
R
)
to have no extreme value, is
1994
233
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A
p
2
<
3
q
B
2
p
2
<
q
C
p
2
<
4
1
q
D
p
2
>
3
q
Solution:
Given,
f
(
x
)
=
x
3
+
p
x
2
+
q
x
+
r
Now,
f
′
(
x
)
=
3
x
2
+
2
x
p
+
q
Clearly
f
′
(
x
)
>
0
Now,
b
2
−
4
a
c
<
0
⇒
4
p
2
−
4
×
3
×
q
<
0
⇒
4
p
2
−
12
q
<
0
⇒
p
2
<
3
q