Question

The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal $M$ is:
$M(s)\mid M^{+}$($aq:0.05$ molar) $\Vert M^{+}$( $aq:1$ molar) $\mid M(s)$ For the above electrolytic cell the magnitude of the cell potential $\left|E_{\text{cell }}\right|=70mV$
If the $0.05$ molar solution of $M^{+}$is replaced by a $0.0025$ molar $M^{+}$solution, then the magnitude of the cell potential would be

• A. 35 mV
• B. 70 mV
• C. 140 mV
• D. 700 mV

Answer 1

Answer: (C)

From above equation $\frac{2.303RT}{F}=0.0538$
So, $E_{\text{cell }}=E_{cat}^{\circ }-\frac{0.0538}{1}\log 0.0025$
$=0-\frac{0.0538}{1}\log 0.0025$
$\approx 0.13988V$
$\approx 140mV$