The compressibility of water is 4 × 10-5 per unit atmospheric pressure. The decrease in volume of 100 cm 3 of water under a pressure of 100 atmosphere will be

Question

The compressibility of water is 4 × 10-5 per unit atmospheric pressure. The decrease in volume of 100 cm 3 of water under a pressure of 100 atmosphere will be (A) 0.4 cm 3 (B) 4 × 10-5 cm 3 (C) 0.025 cm 3 (D) 0.004 cm 3

Tardigrade Admin · Accepted Answer

Compressibility =(1/B)=(Δ V / V/P). Here, P=100 atm Compressibility =4 × 10-5 and V =100 cm 3 Hence, Δ V =0.4 cm 3

Q. The compressibility of water is $4 \times 1 0^{- 5}$ per unit atmospheric pressure. The decrease in volume of $100 c m^{3}$ of water under a pressure of $100$ atmosphere will be

$0.4 c m^{3}$

$4 \times 1 0^{- 5} c m^{3}$

$0.025 c m^{3}$

$0.004 c m^{3}$

Compressibility $= \frac{1}{B} = \frac{Δ V / V}{P}$ .
Here, $P = 100 a t m$
Compressibility $= 4 \times 1 0^{- 5}$ and $V = 100 c m^{3}$
Hence, $Δ V = 0.4 c m^{3}$

Q. The compressibility of water is 4×10−5 per unit atmospheric pressure. The decrease in volume of 100cm3 of water under a pressure of 100 atmosphere will be

0.4cm3

4×10−5cm3

0.025cm3

0.004cm3